Probably not. Even with a hand calculator this would be tedious.
There is a formula for the sum of even integers from 0 to N. There are formulas for the sum of odd integers from 0 to N, and for the sum of all integers from 0 to N (look in your calculus book if you are interested). But pretend that you don't know that. Let us write a program that calculates these three things. The user enters N, and the program counts up from zero to N, adding each number to the appropriate sum.
Here is a skeleton for the program:
import java.io.*;
// User enters a value N
// Add up odd integers, even integers, and all integers 0 to N
//
class addUpIntegers
{
public static void main (String[] args ) throws IOException
{
BufferedReader userin = new BufferedReader (new InputStreamReader(System.in));
String inputData;
int N, sumAll = 0, sumEven = 0, sumOdd = 0;
System.out.println( "Enter limit value:" );
inputData = userin.readLine();
N = Integer.parseInt( inputData );
int count = __________________
while ( ________________ )
{
(more statements will go here later.)
__________________
}
System.out.print ( "Sum of all : " + sumAll );
System.out.print ( "\tSum of even: " + sumEven );
System.out.println( "\tSum of odd : " + sumOdd );
}
}