Probably not. Even with a hand calculator this would be tedious.
There is a formula for the sum of even integers from 0 to N. There are formulas for the sum of odd integers from 0 to N, and for the sum of all integers from 0 to N (look in your calculus book if you are interested). But pretend that you don't know that. Let us write a program that calculates these three things. The user enters N, and the program counts up from zero to N, adding each number to the appropriate sum.
Here is a skeleton for the program:
import java.io.*; // User enters a value N // Add up odd integers, even integers, and all integers 0 to N // class addUpIntegers { public static void main (String[] args ) throws IOException { BufferedReader userin = new BufferedReader (new InputStreamReader(System.in)); String inputData; int N, sumAll = 0, sumEven = 0, sumOdd = 0; System.out.println( "Enter limit value:" ); inputData = userin.readLine(); N = Integer.parseInt( inputData ); int count = __________________ while ( ________________ ) { (more statements will go here later.) __________________ } System.out.print ( "Sum of all : " + sumAll ); System.out.print ( "\tSum of even: " + sumEven ); System.out.println( "\tSum of odd : " + sumOdd ); } }