Yes. New lines are inserted into the program to show this:
In the revised program, the print()
method is used
first with one array, and then with the other array.
This is possible because the parameter x
of the method
refers to the current array,
whichever one is used in the method "call."
import java.io.*; class ArrayOps { void print( int[] x ) { for ( int index=0; index < x.length; index++ ) System.out.print( x[index] + " " ); System.out.println(); } } class ArrayDemo { public static void main ( String[] args ) { ArrayOps operate = new ArrayOps(); int[] ar1 = { -20, 19, 1, 5, -1, 27, 19, 5 } ; int[] ar2 = { 2, 4, 1, 2, 6, 3, 6, 9 } ; System.out.print ("\nThe array is: " ); operate.print( ar1 ); // method call with the 1st array System.out.print ("\nThe second array is: " ); operate.print( ar2 ); // method call with the 2nd array } }
The program will print the following:
C:\>java ArrayDemo The array is:-20 19 1 5 -1 27 19 5 The second array is: 2 4 1 2 6 3 6 9