Yes. New lines are inserted into the program to show this:
In the revised program, the findMax()
method is used
first with one array, and then with the other array.
This is possible because the parameter x
of the method
refers to the current array,
whichever one is used in the method call.
class ArrayOps { int findMax( int[] x ) // this method is called with. { int max = x[0]; for ( int index=0; index <x.length; index++ ) if ( x[index] > max ) max = x[index] ; return max ; } } class ArrayDemo { public static void main ( String[] args ) { ArrayOps operate = new ArrayOps(); int[] ar1 = { -20, 19, 1, 5, -1, 27, 19, 5 } ; int[] ar2 = { 2, 4, 1, 2, 6, 3, 6, 9 } ; System.out.println("The first maximum is: " + operate.findMax( ar1 ) ); System.out.println("The second maximum is: " + operate.findMax( ar2 ) ); } }
The program prints:
C:\>java ArrayDemo The first maximum is: 27 The second maximum is: 9
int
?