Angles Greater than 90
qu = (0.0, 1)T and zu = (-0.5, -0.866)T
The angle between the two vectors is greater than 90°, so the cosine is negative.
Now, cos θ = -0.866. So θ = arc cos -0.866 = 150°.
qu = (0.0, 1)T and zu = (-0.5, -0.866)T
The angle between the two vectors is greater than 90°, so the cosine is negative.
In the diagram above, mentally draw the other vector that has a dot product of -0.866 with vector qu.