Re: Shift limits

Bresticker, Shalom wrote:

>In Verilog, it is well defined. You should keep shifting in zeroes as
>many times as specified. So the result would be zero. This is often
>useful.
>  
>
Hi

Thanks Shalom and Marq. This is what I expected. I had doubts when I 
tried to implement Verilog << directly in C/C++, for example, with the 
wonderful C++ overloaded left shift operator:

int i = 1;
cout << hex << (i << 33) << endl;

Which compiles with a warning and prints "2" - seemingly the shift is 
done modulo the word size in bits.

Regards
Paul Floyd

-- 
Dr. Paul Floyd
Mentor Graphics Corporation



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