No — array indexes start at zero, and go up to length-1.
Here is a program that asks the user for an integer and for
an array index where it is to be placed.
Only indexes 0 through 9 are allowed.
Any other index causes an
IndexOutOfBoundsException.
import java.util.* ;
public class IndexPractice
{
public static void main ( String[] a )
{
Scanner scan = new Scanner( System.in );
int data=0, slot=0 ;
int[] value = new int[10];
try
{
System.out.print("Enter the data: ");
data = scan.nextInt();
System.out.print("Enter the array index: ");
slot = scan.nextInt();
value[slot] = data;
}
catch (InputMismatchException ex )
{
System.out.println("This is your problem: " + ex.getMessage()
+ "\nHere is where it happened:\n");
ex.printStackTrace();
}
catch (IndexOutOfBoundsException ex )
{
System.out.println("This is your problem: " + ex.getMessage()
+ "\nHere is where it happened:\n");
ex.printStackTrace();
}
System.out.println("Good-by" );
}
}
If the user enters:
Enter the data: 8 Enter the array index: 10will an exception be thrown?