No.
The bytes on the disk are just raw bytes. You (the programmer) have to know what you wrote in order to make sense of it. Here is another program:
import java.io.*;
class TwoShorts
{
  public static void main ( String[] args ) throws IOException
  {
    String fileName = "mixedTypes.dat" ;
    DataOutputStream dataOut = new DataOutputStream(
        new BufferedOutputStream(
        new FileOutputStream( fileName  ) ) );
    dataOut.writeShort( 0 );
    dataOut.writeShort( 0 );
    dataOut.writeDouble( 12.45 );
    dataOut.close();
  }
}
 
Two 16-bit shorts are written, each containing a zero.
The previous program wrote a 32-bit zero.
The double is the same as before.
What will the output file look like?