This section summarizes and extends the above derivations in a more
formal manner (following portions of chapter 4 of
). In
particular, we establish that the sum of projections of
onto vectors
will give back the original vector
whenever the set
is an *orthogonal
basis* for .

**Definition: **A set of vectors is said to form a *vector space* if, given
any two members and from the set, the vectors
and are also in the set, where
is any
scalar.

**Definition: **The set of all -dimensional complex vectors is denoted
. That is, consists of all vectors
defined as a list of complex numbers
.

**Theorem: ** is a *vector space* under elementwise addition and
multiplication by complex scalars.

*Proof: *This is a special case of the following more general theorem.

**Theorem: **Let be an integer greater than 0. Then the set of all
linear combinations of vectors from forms a vector space
under elementwise addition and multiplication by complex scalars.

*Proof: *Let the original set of vectors be denoted
.
Form

which is yet another linear combination of the original vectors (since complex numbers are closed under addition). Since we have shown that scalar multiples and vector sums of linear combinations of the original vectors from are also linear combinations of those same original vectors from , we have that the defining properties of a vector space are satisfied.

Note that the closure of vector addition and scalar multiplication are ``inherited'' from the closure of complex numbers under addition and multiplication.

**Corollary: **The set of all linear combinations of *real* vectors
, using real scalars
, form a
vector space.

**Definition: **The set of all linear combinations of a set of
*complex* vectors from , using complex scalars, is called a
*complex vector space* of dimension .

**Definition: **The set of all linear combinations of a set of *real* vectors
from , using real scalars, is called a *real vector
space* of dimension .

**Definition: **If a vector space consists of the set of all linear
combinations of a finite set of vectors
, then
those vectors are said to *span* the space.

**Example: **The *coordinate vectors* in span since every vector
can be expressed as a linear combination of the coordinate vectors
as

**Definition: **The vector space spanned by a set of vectors from
is called an -dimensional *subspace* of .

**Definition: **A vector
is said to be *linearly dependent* on
a set of vectors
,
, if
can be expressed as a linear combination of those vectors.

Thus, is linearly dependent on if there exist scalars such that . Note that the zero vector is linearly dependent on every collection of vectors.

**Theorem: **(i) If
span a vector space, and if one of them,
say , is linearly dependent on the others, then the same vector
space is spanned by the set obtained by omitting from the
original set. (ii) If
span a vector space,
we can always select from these a linearly independent set that spans
the same space.

*Proof: *Any in the space can be represented as a linear combination of the
vectors
. By expressing as a linear
combination of the other vectors in the set, the linear combination
for becomes a linear combination of vectors other than .
Thus, can be eliminated from the set, proving (i). To prove
(ii), we can define a procedure for forming the required subset of the
original vectors: First, assign to the set. Next, check to
see if and are linearly dependent. If so (*i.e.*,
is a scalar times ), then discard ; otherwise
assign it also to the new set. Next, check to see if is
linearly dependent on the vectors in the new set. If it is (*i.e.*,
is some linear combination of and ) then
discard it; otherwise assign it also to the new set. When this
procedure terminates after processing , the new set will
contain only linearly independent vectors which span the original
space.

**Definition: **A set of linearly independent vectors which spans a vector space
is called a *basis* for that vector space.

**Definition: **The set of coordinate vectors in
is called the *natural basis* for , where the th basis vector
is

**Theorem: **The linear combination expressing a vector in terms of basis vectors
for a vector space is *unique*.

*Proof: *Suppose a vector
can be expressed in two different ways as
a linear combination of basis vectors
:

where for at least one value of . Subtracting the two representations gives

Note that while the linear combination relative to a particular basis is
unique, the choice of basis vectors is not. For example, given any basis
set in , a new basis can be formed by *rotating* all vectors in
by the same angle. In this way, an infinite number of basis sets can
be generated.

As we will soon show, the DFT can be viewed as a *change of
coordinates* from coordinates relative to the *natural basis* in ,
, to coordinates relative to the *sinusoidal
basis* for ,
, where
. The sinusoidal basis set for consists of length
sampled complex sinusoids at frequencies
. Any scaling of these vectors in by complex
scale factors could also be chosen as the sinusoidal basis (*i.e.*, any
nonzero amplitude and any phase will do). However, for simplicity, we will
only use unit-amplitude, zero-phase complex sinusoids as the Fourier
``frequency-domain'' basis set. To summarize this paragraph, the
time-domain samples of a signal are its coordinates relative to the natural
basis for , while its spectral coefficients are the coordinates of the
signal relative to the sinusoidal basis for .

**Theorem: **Any two bases of a vector space contain the same number of vectors.

*Proof: *Left as an exercise (or see [46]).

**Definition: **The number of vectors in a basis for a particular space is called
the *dimension* of the space. If the dimension is , the space is
said to be an * dimensional space*, or *-space*.

In this book, we will only consider finite-dimensional vector spaces in any detail. However, the discrete-time Fourier transform (DTFT) and Fourier transform (FT) both require infinite-dimensional basis sets, because there is an infinite number of points in both the time and frequency domains. (See Appendix B for details regarding the FT and DTFT.)

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