Consider the problem of finding the position of an item in a sorted list. I.e., given the sorted sequence and an item x, find i (if it exists) such that . The usual solution to this problem is binary search .
Binary search is a divide-and-conquer strategy. The sequence S is split into two subsequences, and . The original problem is split into two subproblems: Find x in or . Of course, since the original list is sorted, we can quickly determine the list in which x must appear. Therefore, we only need to solve one subproblem.
Program defines the function BinarySearch which takes four arguments, array, x, i and n. This routine looks for the position in array at which item x is found. Specifically, it considers the following elements of the array:
Program: Divide-and-Conquer Example--Binary Search
The running time of the algorithm is clearly a function of n, the number of elements to be searched. Although Program works correctly for arbitrary values of n, it is much easier to determine the running time if we assume that n is a power of two. In this case, the running time is given by the recurrence
Equation is easily solved using repeated substitution:
Setting gives .