Consider the function which is shown in Figure . Clearly, f(n) is non-negative for all integers . We wish to show that . According to Definition , in order to show this we need to find an integer and a constant c>0 such that for all integers , .
As with big oh, it does not matter what the particular constants are--as long as they exist! E.g., suppose we choose c=1. Then
Since for all values of , we conclude that .
So, we have that for c=1 and , for all integers . Hence, . Figure clearly shows that the function is less than the function f(n)=5n-64n+256 for all values of . Of course, there are many other values of c and that will do. For example, c=2 and .