> edaorg@v-ms.com wrote: > > Geoffrey.Coram wrote: > > > electrical p,n; > > > > analog begin : test1 > > I(p,n) <+ 5.0; > > end > > > > analog continue : test1 > > V(p,n) <+ 0.0; > > end > > > > analog continue : test1 > > I(p,n) <+ 3.0; > > end [snip] > But if they are not concatenated it doesn't matter if they are in the > same module or seperate modules, you still have the same problem > (i.e no ordering). If they are in separate modules, then it's like you have two current sources and a voltage source connected across the same two nodes. The voltage is 0, and the v-source takes 8A plus whatever the rest of the circuit contributes. > I would have said (with my EE hat on) that the obvious result of the > above example is 0V across (p,n) and 8A through it, ordering is immaterial. If the analog blocks are concatenated to get analog begin I(p,n) <+ 5.0; V(p,n) <+ 0.0; I(p,n) <+ 3.0; end then the result is 3A between p and n, with no constraint (from this module) on the voltage. -Geoffrey -- This message has been scanned for viruses and dangerous content by MailScanner, and is believed to be clean.Received on Wed Jan 3 05:28:41 2007
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